Asynchronous array loops in JavaScript

Angelos Chalaris · JavaScript, Array, Function, Promise · Jun 12, 2021

Asynchronous operations seem to trip up a lot of developers. This is especially true when combined with looping over arrays, as there are some caveats that come with each option available.

For loops

Combining async with a for (or a for...of) loop is possibly the most straightforward option when performing asynchronous operations over array elements. Using await inside a for loop will cause the code to stop and wait for the asynchronous operation to complete before continuing. This means that all promises will be run sequentially.

const asyncUppercase = item =>
  new Promise(resolve =>
    setTimeout(
      () => resolve(item.toUpperCase()),
      Math.floor(Math.random() * 1000)
    )
  );

const uppercaseItems = async () => {
  const items = ['a', 'b', 'c'];
  for (item of items) {
    const uppercaseItem = await asyncUppercase(item);
    console.log(uppercaseItem);
  }

  console.log('Items processed');
};

uppercaseItems();
// LOGS: 'A', 'B', 'C', 'Items processed'

Promises

Promise.all() provides another option for asynchronous loops over arrays. The main difference with the previous one is that Promise.all() executes all asynchronous operations in parallel. This means that promises will execute out of order, which might be an issue in some cases. Most often than not, this is my preferred solution as it's quite uncommon to want promises to execute sequentially.

const asyncUppercase = item =>
  new Promise(resolve =>
    setTimeout(
      () => resolve(item.toUpperCase()),
      Math.floor(Math.random() * 1000)
    )
  );

const uppercaseItems = () => {
  const items = ['a', 'b', 'c'];
  return Promise.all(
    items.map(async item => {
      const uppercaseItem = await asyncUppercase(item);
      console.log(uppercaseItem);
    })
  ).then(() => {
    console.log('Items processed');
  });
};
// LOGS: 'A', 'C', 'B', 'Items processed'

Array methods

Unfortunately, array methods such as Array.prototype.forEach() do not work well with async/await. The only viable solution is to use Promise.all() as shown in the previous example. Using an async callback with Array.prototype.forEach() will result in the rest of the code executing and the asynchronous operations not being awaited for.

const asyncUppercase = item =>
  new Promise(resolve =>
    setTimeout(
      () => resolve(item.toUpperCase()),
      Math.floor(Math.random() * 1000)
    )
  );

const uppercaseItems = async () => {
  const items = ['a', 'b', 'c'];
  await items.forEach(async item => {
    const uppercaseItem = await asyncUppercase(item);
    console.log(uppercaseItem);
  });

  console.log('Items processed');
};

uppercaseItems();
// LOGS: ''Items processed', 'B', 'A', 'C'

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