JavaScript, Array · Oct 20, 2020
Returns the elements that exist in both arrays, filtering duplicate values.
Set from b, then use Array.prototype.filter() on a to only keep values contained in b.const intersection = (a, b) => {
const s = new Set(b);
return [...new Set(a)].filter(x => s.has(x));
};intersection([1, 2, 3], [4, 3, 2]); // [2, 3]
Learn how to apply mathematical set operations to JavaScript arrays.
Collection · 12 snippets
Returns the elements that exist in both arrays, after applying the provided function to each array element of both.
JavaScript, Array · Oct 20, 2020
Returns the elements that exist in both arrays, using a provided comparator function.
JavaScript, Array · Oct 20, 2020
Mutates the original array to filter out the values at the specified indexes. Returns the removed elements.
JavaScript, Array · Oct 22, 2020