Skip to content

Bifurcate list based on function

Splits values into two groups, based on the result of the given filtering function.

Use a list comprehension to add elements to groups, based on the value returned by fn for each element.
If fn returns a truthy value for any element, add it to the first group, otherwise add it to the second group.

def bifurcate_by(lst, fn):
  return [
    [x for x in lst if fn(x)],
    [x for x in lst if not fn(x)]
  ]

bifurcate_by(['beep', 'boop', 'foo', 'bar'], lambda x: x[0] == 'b')
# [ ['beep', 'boop', 'bar'], ['foo'] ]

More like this

Python · November 2, 2020
Bifurcate list based on values

Splits values into two groups, based on the result of the given filter list.
Python · November 2, 2020
List difference based on function

Returns the difference between two lists, after applying the provided function to each list element of both.
Python · November 2, 2020
List symmetric difference based on function

Returns the symmetric difference between two lists, after applying the provided function to each list element of both.
Python · November 2, 2020
List union based on function

Returns every element that exists in any of the two lists once, after applying the provided function to each element of both.