Sort dictionary by value

Python, Dictionary · Jan 7, 2021

Sorts the given dictionary by value.

Use dict.items() to get a list of tuple pairs from d and sort it using a lambda function and sorted().
Use dict() to convert the sorted list back to a dictionary.
Use the reverse parameter in sorted() to sort the dictionary in reverse order, based on the second argument.
⚠️ NOTICE: Dictionary values must be of the same type.

def sort_dict_by_value(d, reverse = False):
  return dict(sorted(d.items(), key = lambda x: x[1], reverse = reverse))

d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4}
sort_dict_by_value(d) # {'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5}
sort_dict_by_value(d, True)
# {'five': 5, 'four': 4, 'three': 3, 'two': 2, 'one': 1}