Delay async function execution

OSCC · JavaScript, Function, Promise · Oct 22, 2020

Delays the execution of an asynchronous function.

  • Delay executing part of an async function, by putting it to sleep, returning a Promise.
const sleep = ms => new Promise(resolve => setTimeout(resolve, ms));
async function sleepyWork() {
  console.log("I'm going to sleep for 1 second.");
  await sleep(1000);
  console.log('I woke up after 1 second.');

Recommended snippets